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	<title>Comments on: A look at a few Tripos questions X</title>
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		<title>By: robin harte</title>
		<link>http://gowers.wordpress.com/2012/05/29/a-look-at-a-few-tripos-questions-x/#comment-21331</link>
		<dc:creator><![CDATA[robin harte]]></dc:creator>
		<pubDate>Thu, 09 Aug 2012 00:48:20 +0000</pubDate>
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		<description><![CDATA[talking about &quot;normal subgroups&quot; of groups leads me to the idea of &quot;normal&quot; subgroups of semigroups - start with &quot;generalized exponentials&quot; in Banach algebras, they form the connected component of the identity in the invertible group: so what can you say about their left and right cosets in the larger semigroups of left and of right invertibles ? you can still multiply

I am being uncareful here and not checking what I have looked at elsewhere, but the idea is a very simple extension of the usual quotient group idea, and is involved in a discussion of &quot;spectral pictures&quot;]]></description>
		<content:encoded><![CDATA[<p>talking about &#8220;normal subgroups&#8221; of groups leads me to the idea of &#8220;normal&#8221; subgroups of semigroups &#8211; start with &#8220;generalized exponentials&#8221; in Banach algebras, they form the connected component of the identity in the invertible group: so what can you say about their left and right cosets in the larger semigroups of left and of right invertibles ? you can still multiply</p>
<p>I am being uncareful here and not checking what I have looked at elsewhere, but the idea is a very simple extension of the usual quotient group idea, and is involved in a discussion of &#8220;spectral pictures&#8221;</p>
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		<title>By: Stones Cry Out - If they keep silent&#8230; &#187; Things Heard: e223v1n2</title>
		<link>http://gowers.wordpress.com/2012/05/29/a-look-at-a-few-tripos-questions-x/#comment-17899</link>
		<dc:creator><![CDATA[Stones Cry Out - If they keep silent&#8230; &#187; Things Heard: e223v1n2]]></dc:creator>
		<pubDate>Tue, 29 May 2012 13:22:45 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=4283#comment-17899</guid>
		<description><![CDATA[[...] The test approaches, fun with groups. [...]]]></description>
		<content:encoded><![CDATA[<p>[...] The test approaches, fun with groups. [...]</p>
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		<title>By: Monday/Tuesday Highlights &#124; Pseudo-Polymath</title>
		<link>http://gowers.wordpress.com/2012/05/29/a-look-at-a-few-tripos-questions-x/#comment-17898</link>
		<dc:creator><![CDATA[Monday/Tuesday Highlights &#124; Pseudo-Polymath]]></dc:creator>
		<pubDate>Tue, 29 May 2012 13:22:12 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=4283#comment-17898</guid>
		<description><![CDATA[[...] test approaches, fun with [...]]]></description>
		<content:encoded><![CDATA[<p>[...] test approaches, fun with [...]</p>
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	<item>
		<title>By: Gareth</title>
		<link>http://gowers.wordpress.com/2012/05/29/a-look-at-a-few-tripos-questions-x/#comment-17895</link>
		<dc:creator><![CDATA[Gareth]]></dc:creator>
		<pubDate>Tue, 29 May 2012 13:04:32 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=4283#comment-17895</guid>
		<description><![CDATA[The general waffle I often use at the start of the n! part of the Groups question is as follows.  Since my supervisees have found it useful, I thought I&#039;d add it here.

Suppose the group G acts on the set X, and that there are more elements in G than there are things we can actually do to X.  Then, by the pigeonhole principle, some two things in G must have exactly the same effect on X.  So doing one followed by the inverse of the other does nothing to X.

Aha, something does nothing - so there is a non-trivial kernel (to some homomorphism).  Now, is the kernel all of G?  If not, then we have a non-trivial proper normal subgroup.

So, if G does anything at all, and if G is bigger than &#124;X&#124;!, then G can&#039;t be simple.]]></description>
		<content:encoded><![CDATA[<p>The general waffle I often use at the start of the n! part of the Groups question is as follows.  Since my supervisees have found it useful, I thought I&#8217;d add it here.</p>
<p>Suppose the group G acts on the set X, and that there are more elements in G than there are things we can actually do to X.  Then, by the pigeonhole principle, some two things in G must have exactly the same effect on X.  So doing one followed by the inverse of the other does nothing to X.</p>
<p>Aha, something does nothing &#8211; so there is a non-trivial kernel (to some homomorphism).  Now, is the kernel all of G?  If not, then we have a non-trivial proper normal subgroup.</p>
<p>So, if G does anything at all, and if G is bigger than |X|!, then G can&#8217;t be simple.</p>
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