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	<title>Comments on: EDP8 &#8212; what next?</title>
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	<description>Mathematics related discussions</description>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6321</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Fri, 26 Feb 2010 10:05:00 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6321</guid>
		<description><![CDATA[One further remark. It is initially tempting (or at least it was for me) to conjecture that if you choose many intervals along many HAPs, then you are forced to choose a linearly independent set of intervals. However, I have just realized that the usual example, 1, -1, 0, 1, -1, 0, ... shows that that cannot be true, since along every HAP it has a zero sum either always or every third term. The conclusion is that if we take all sets of the form $latex \{md,(m+1)d,(m+2)d\}$ then they (or rather their characteristic functions) are not linearly independent (because they all live in the subspace orthogonal to 1, -1, 0, 1, -1, 0, ...).

But I think that raises an interesting question. If we choose a large set of small segments of HAPs, then must the annihilator of that set consist of very structured functions (e.g. functions that are periodic with period $latex d$ for some small $latex d$ and zero at all multiples of $latex d$)? Since this is a linear algebra question, it might be more approachable that EDP itself, but it also seems close enough that an answer to it could be helpful. Even if that is not the case, I like the question.]]></description>
		<content:encoded><![CDATA[<p>One further remark. It is initially tempting (or at least it was for me) to conjecture that if you choose many intervals along many HAPs, then you are forced to choose a linearly independent set of intervals. However, I have just realized that the usual example, 1, -1, 0, 1, -1, 0, &#8230; shows that that cannot be true, since along every HAP it has a zero sum either always or every third term. The conclusion is that if we take all sets of the form <img src='http://s0.wp.com/latex.php?latex=%5C%7Bmd%2C%28m%2B1%29d%2C%28m%2B2%29d%5C%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;{md,(m+1)d,(m+2)d&#92;}' title='&#92;{md,(m+1)d,(m+2)d&#92;}' class='latex' /> then they (or rather their characteristic functions) are not linearly independent (because they all live in the subspace orthogonal to 1, -1, 0, 1, -1, 0, &#8230;).</p>
<p>But I think that raises an interesting question. If we choose a large set of small segments of HAPs, then must the annihilator of that set consist of very structured functions (e.g. functions that are periodic with period <img src='http://s0.wp.com/latex.php?latex=d&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d' title='d' class='latex' /> for some small <img src='http://s0.wp.com/latex.php?latex=d&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d' title='d' class='latex' /> and zero at all multiples of <img src='http://s0.wp.com/latex.php?latex=d&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d' title='d' class='latex' />)? Since this is a linear algebra question, it might be more approachable that EDP itself, but it also seems close enough that an answer to it could be helpful. Even if that is not the case, I like the question.</p>
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		<title>By: Gil Kalai</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6310</link>
		<dc:creator><![CDATA[Gil Kalai]]></dc:creator>
		<pubDate>Thu, 25 Feb 2010 17:38:57 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6310</guid>
		<description><![CDATA[That&#039;s quite interesting! I like this linear algebra idea.

A few remarks:

1) Actually we do not have to determine $latex \cal A$ in advance: we only need to assume we can partition the HAP to intervals of length proportional to k (say between k/100 and 100k) so that the equations will be satisfied. (We have a considerable freedom to chose the equations that will still to the discrepency being likely small.)


2) The linear algebra consideration can go both ways. If you can show using linear algebra that you cannot have the zeros of the sums on all HAP being too &quot;close by&quot; (say uniformly below some constant) this will come close of proving EDP.

(And as a meta comment: trying other techniques like linear algebra methods or polynomial methods or probabilistic methods seem quite reasonable for EDP. unlike DHJ i dont think we have a propri much knowledge which tricks will be relevant.)


3) Strangely we need to understand how such conditions on HAP with large periods depend on conditions for HAP with small periods; Both in terms of &quot;statistical dependence&quot; (my heuristic comment) and in terms of &quot;linear algebra dependence&quot; (your comment).

4) Also the problem of trying to get by stochastic methods low discrepency sequence has a feeling like random walks with various stochastic tools to make the walks frequently return to zero. (Simultaniously for all HAP). It seems we discussed such &quot;biased&quot; random walks before but I dont remember when.

5) Anyway these heuristics taking also with the linear algebra concerns still suggest that discrepency sqrt log n might be possible.]]></description>
		<content:encoded><![CDATA[<p>That&#8217;s quite interesting! I like this linear algebra idea.</p>
<p>A few remarks:</p>
<p>1) Actually we do not have to determine <img src='http://s0.wp.com/latex.php?latex=%5Ccal+A&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;cal A' title='&#92;cal A' class='latex' /> in advance: we only need to assume we can partition the HAP to intervals of length proportional to k (say between k/100 and 100k) so that the equations will be satisfied. (We have a considerable freedom to chose the equations that will still to the discrepency being likely small.)</p>
<p>2) The linear algebra consideration can go both ways. If you can show using linear algebra that you cannot have the zeros of the sums on all HAP being too &#8220;close by&#8221; (say uniformly below some constant) this will come close of proving EDP.</p>
<p>(And as a meta comment: trying other techniques like linear algebra methods or polynomial methods or probabilistic methods seem quite reasonable for EDP. unlike DHJ i dont think we have a propri much knowledge which tricks will be relevant.)</p>
<p>3) Strangely we need to understand how such conditions on HAP with large periods depend on conditions for HAP with small periods; Both in terms of &#8220;statistical dependence&#8221; (my heuristic comment) and in terms of &#8220;linear algebra dependence&#8221; (your comment).</p>
<p>4) Also the problem of trying to get by stochastic methods low discrepency sequence has a feeling like random walks with various stochastic tools to make the walks frequently return to zero. (Simultaniously for all HAP). It seems we discussed such &#8220;biased&#8221; random walks before but I dont remember when.</p>
<p>5) Anyway these heuristics taking also with the linear algebra concerns still suggest that discrepency sqrt log n might be possible.</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6283</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Wed, 24 Feb 2010 09:57:25 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6283</guid>
		<description><![CDATA[A general question that occurred to me was this. Suppose you have a finite set $latex X$ and a collection $latex \mathcal{A}$ of subsets of $latex X$ of even cardinality. Under what conditions can you find a function $latex f:X\rightarrow\{-1,1\}$ such that $latex \sum_{x\in A}f(x)=0$ for every $latex A\in\mathcal{A}$? 

My guess is that this problem would be NP-complete in general, so the best one could hope for is a sufficient condition for such a function to exist. The motivation for the question is that one way of restricting the growth along a HAP is to insist, fairly frequently, that the sum is zero. This gives us a collection $latex \mathcal{A}$ as above, and the question is how &quot;dense&quot; we can make it.

A small remark is that if we take the linear relaxation (that is, we allow $latex f$ to take arbitrary real values) then we always have the trivial solution of setting $latex f$ to be identically zero, and we have non-trivial solutions only if the characteristic functions of the sets $latex A\in\mathcal{A}$ are linearly independent. If we decide that the sum should be zero at every $latex k$th number along each HAP, then the HAP with common difference $latex d$ gives rise to around $latex n/dk$ linear conditions, so the total number of conditions we need is $latex (n/k)(1+1/2+\dots+1/(n/k))$, which (for smallish $latex k$) is around $latex n\log n/k$. This suggests that there is something natural about the $latex \log n$ bound. (Of course, it is possible that there will be dependencies amongst the various conditions, but at first glance they look fairly independent to me.)]]></description>
		<content:encoded><![CDATA[<p>A general question that occurred to me was this. Suppose you have a finite set <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='X' title='X' class='latex' /> and a collection <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BA%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mathcal{A}' title='&#92;mathcal{A}' class='latex' /> of subsets of <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='X' title='X' class='latex' /> of even cardinality. Under what conditions can you find a function <img src='http://s0.wp.com/latex.php?latex=f%3AX%5Crightarrow%5C%7B-1%2C1%5C%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f:X&#92;rightarrow&#92;{-1,1&#92;}' title='f:X&#92;rightarrow&#92;{-1,1&#92;}' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7Bx%5Cin+A%7Df%28x%29%3D0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{x&#92;in A}f(x)=0' title='&#92;sum_{x&#92;in A}f(x)=0' class='latex' /> for every <img src='http://s0.wp.com/latex.php?latex=A%5Cin%5Cmathcal%7BA%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A&#92;in&#92;mathcal{A}' title='A&#92;in&#92;mathcal{A}' class='latex' />? </p>
<p>My guess is that this problem would be NP-complete in general, so the best one could hope for is a sufficient condition for such a function to exist. The motivation for the question is that one way of restricting the growth along a HAP is to insist, fairly frequently, that the sum is zero. This gives us a collection <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BA%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mathcal{A}' title='&#92;mathcal{A}' class='latex' /> as above, and the question is how &#8220;dense&#8221; we can make it.</p>
<p>A small remark is that if we take the linear relaxation (that is, we allow <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> to take arbitrary real values) then we always have the trivial solution of setting <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> to be identically zero, and we have non-trivial solutions only if the characteristic functions of the sets <img src='http://s0.wp.com/latex.php?latex=A%5Cin%5Cmathcal%7BA%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A&#92;in&#92;mathcal{A}' title='A&#92;in&#92;mathcal{A}' class='latex' /> are linearly independent. If we decide that the sum should be zero at every <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='k' title='k' class='latex' />th number along each HAP, then the HAP with common difference <img src='http://s0.wp.com/latex.php?latex=d&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d' title='d' class='latex' /> gives rise to around <img src='http://s0.wp.com/latex.php?latex=n%2Fdk&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n/dk' title='n/dk' class='latex' /> linear conditions, so the total number of conditions we need is <img src='http://s0.wp.com/latex.php?latex=%28n%2Fk%29%281%2B1%2F2%2B%5Cdots%2B1%2F%28n%2Fk%29%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='(n/k)(1+1/2+&#92;dots+1/(n/k))' title='(n/k)(1+1/2+&#92;dots+1/(n/k))' class='latex' />, which (for smallish <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='k' title='k' class='latex' />) is around <img src='http://s0.wp.com/latex.php?latex=n%5Clog+n%2Fk&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n&#92;log n/k' title='n&#92;log n/k' class='latex' />. This suggests that there is something natural about the <img src='http://s0.wp.com/latex.php?latex=%5Clog+n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;log n' title='&#92;log n' class='latex' /> bound. (Of course, it is possible that there will be dependencies amongst the various conditions, but at first glance they look fairly independent to me.)</p>
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		<title>By: Gil Kalai</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6282</link>
		<dc:creator><![CDATA[Gil Kalai]]></dc:creator>
		<pubDate>Wed, 24 Feb 2010 09:23:03 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6282</guid>
		<description><![CDATA[Well, if one drunk person goes at each time-period left and right with probability 1/2 and his lazy twin brother makes precisely the same moves on odd time-periods and stays still on even times periods, then the probabilities for them to end very near to the origin are positively correlated. So I think positive correlation for the kind of events I considered is roughly the &quot;first order&quot; behavior. (I think you are right that there may be subtle negative correlations floating around.) 

If my heuristic idea is roughly ok (and it is quite possible I made a serious mistake there), then I would expect that log n discrepency sequences (perhaos even logn^{1/2+epsilon)) will be a rare but positive-probability events, (the number of such sequences will still be exponential), so I would not believe some subtle negative correlation will interfere (of course, proving this is a different matter). 

There is some little hope that positive correlations will somehow allow constant-discrepency sequences. 

This also suggests  that finding in an arbitrary +-1 sequence an interval in an HOP with large discrepency using a pobabilistic argument is something worth trying. But the big obstacle here (as before) would be how to distinguish a +-1 sequence from a 0 +1 -1 sequence.]]></description>
		<content:encoded><![CDATA[<p>Well, if one drunk person goes at each time-period left and right with probability 1/2 and his lazy twin brother makes precisely the same moves on odd time-periods and stays still on even times periods, then the probabilities for them to end very near to the origin are positively correlated. So I think positive correlation for the kind of events I considered is roughly the &#8220;first order&#8221; behavior. (I think you are right that there may be subtle negative correlations floating around.) </p>
<p>If my heuristic idea is roughly ok (and it is quite possible I made a serious mistake there), then I would expect that log n discrepency sequences (perhaos even logn^{1/2+epsilon)) will be a rare but positive-probability events, (the number of such sequences will still be exponential), so I would not believe some subtle negative correlation will interfere (of course, proving this is a different matter). </p>
<p>There is some little hope that positive correlations will somehow allow constant-discrepency sequences. </p>
<p>This also suggests  that finding in an arbitrary +-1 sequence an interval in an HOP with large discrepency using a pobabilistic argument is something worth trying. But the big obstacle here (as before) would be how to distinguish a +-1 sequence from a 0 +1 -1 sequence.</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6281</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Wed, 24 Feb 2010 08:47:58 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6281</guid>
		<description><![CDATA[Sune&#039;s question is one I want to know the answer to as well, but I&#039;ve been too lazy to get hold of the paper.]]></description>
		<content:encoded><![CDATA[<p>Sune&#8217;s question is one I want to know the answer to as well, but I&#8217;ve been too lazy to get hold of the paper.</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6280</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Wed, 24 Feb 2010 08:46:16 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6280</guid>
		<description><![CDATA[I find this line of thought interesting, and I would certainly be very interested indeed in a proof that there were many examples with logarithmic discrepancy.

One thing I didn&#039;t understand was your assertion that the correlations were positive. For example, it looks as though by far the easiest way to make the discrepancy small along all HAPs with odd common difference is to take a periodic sequence such as 1, -1, 1, -1, ... or 1, 1, -1, -1, 1, 1, -1, -1, ...  which suggests a negative correlation with low discrepancy along HAPs with common difference a power of 2. 

It could be that this heuristic argument breaks down if one looks only at logarithmic discrepancy, but I still don&#039;t see any evidence for positive correlation. Indeed, the rough picture I had in mind was that there was &lt;em&gt;negative&lt;/em&gt; correlation, in that in general it seems that periodicity tends to help a lot with some common differences and be a big problem for others. Or perhaps I mean something a bit more complicated, like positive pairwise correlation but with negative correlations coming in when one tries to ensure many events all at once. (If EDP is true then something like this seems to be the case, since we probably do have reasonable pairwise correlations but we know that we can&#039;t get all the events to hold simultaneously. But again I&#039;m talking about bounded discrepancy rather than logarithmic discrepancy here.)]]></description>
		<content:encoded><![CDATA[<p>I find this line of thought interesting, and I would certainly be very interested indeed in a proof that there were many examples with logarithmic discrepancy.</p>
<p>One thing I didn&#8217;t understand was your assertion that the correlations were positive. For example, it looks as though by far the easiest way to make the discrepancy small along all HAPs with odd common difference is to take a periodic sequence such as 1, -1, 1, -1, &#8230; or 1, 1, -1, -1, 1, 1, -1, -1, &#8230;  which suggests a negative correlation with low discrepancy along HAPs with common difference a power of 2. </p>
<p>It could be that this heuristic argument breaks down if one looks only at logarithmic discrepancy, but I still don&#8217;t see any evidence for positive correlation. Indeed, the rough picture I had in mind was that there was <em>negative</em> correlation, in that in general it seems that periodicity tends to help a lot with some common differences and be a big problem for others. Or perhaps I mean something a bit more complicated, like positive pairwise correlation but with negative correlations coming in when one tries to ensure many events all at once. (If EDP is true then something like this seems to be the case, since we probably do have reasonable pairwise correlations but we know that we can&#8217;t get all the events to hold simultaneously. But again I&#8217;m talking about bounded discrepancy rather than logarithmic discrepancy here.)</p>
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		<title>By: Sune Kristian Jakobsen</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6279</link>
		<dc:creator><![CDATA[Sune Kristian Jakobsen]]></dc:creator>
		<pubDate>Wed, 24 Feb 2010 08:32:26 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6279</guid>
		<description><![CDATA[How was the $latex cN^{1/4}$-bound for general APs proved?]]></description>
		<content:encoded><![CDATA[<p>How was the <img src='http://s0.wp.com/latex.php?latex=cN%5E%7B1%2F4%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='cN^{1/4}' title='cN^{1/4}' class='latex' />-bound for general APs proved?</p>
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		<title>By: Gil Kalai</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6278</link>
		<dc:creator><![CDATA[Gil Kalai]]></dc:creator>
		<pubDate>Wed, 24 Feb 2010 07:16:38 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6278</guid>
		<description><![CDATA[I thought that maybe it will be a good idea to try even superficially some orthogonal ideas (at least to my own, it is so not easy keeping track). 

First, a remark: It looks that the only definite result in the positive direction is about functions correlated with a character and I would be happy if somebody can explain informally, &quot;why&quot; this result is true, and does it &quot;explain&quot; the observed log-n discrepency.


So I thought about  probabilistic heuristical  ideas towards sequences with low discrepency.

How to construct prove using a random method that sequences with low discrepency exist? or even to estimate roughly the number of such sequences? Heuristically, if we want to keep the discrepency on a AP  below K we need to impose conditions on intervals of length about $latex K^2$ or a little less. (If we assume that $latex x_1+...+x_m=0$ then we can be pretty sure that the partial sums are below $latex \sqrt m$ or so.)

Altogether on all HAP we have nlogn/(K^2) conditions; and each one represents an event whose probability is roughly 1/K, so a rough estimate of the overall probability for a sequence to satisfy all these conditions is (1/K)^nlogn/K^2 which should be larger than 2^-n.

So if K is  little more than sqrt log n it looks good.

There are now good news and bad news:

The bad news is that we do not have independence. There are methods to prove the existence of rare events even if there is some slight dependencies (e.g., Lovasz Local Lemma) but you still need much more independence.

The good news is that it seems that the correlation is positive. So if you already assume that sums of $latex x_i$s is zero (or close to zero) for certain entervals in some HAP then it is more likely that such sums are zero when you take sums along intervals in other HAP. 

But the good news are not that good in the sense that I see no (even heuristically) reason to believe that this positive correlation will replace the 1/K with something larger than 1/2 and this will not make a big difference. (But this deserves more thinking.)

What about general AP (just as a sanity test). Here, the n log n is replaced by n^2 so K indeed is expected to be larger. It would be interesting to compare the discrepency results for AP (Roth?) with what the probabilistic heuristic gives to get some intuition.

If such a heuristic can show that the probability for a sequence with low discrepency (say polylog n) is sufficiently large, I see no reason why such low discrepency will force some periodic behavior.]]></description>
		<content:encoded><![CDATA[<p>I thought that maybe it will be a good idea to try even superficially some orthogonal ideas (at least to my own, it is so not easy keeping track). </p>
<p>First, a remark: It looks that the only definite result in the positive direction is about functions correlated with a character and I would be happy if somebody can explain informally, &#8220;why&#8221; this result is true, and does it &#8220;explain&#8221; the observed log-n discrepency.</p>
<p>So I thought about  probabilistic heuristical  ideas towards sequences with low discrepency.</p>
<p>How to construct prove using a random method that sequences with low discrepency exist? or even to estimate roughly the number of such sequences? Heuristically, if we want to keep the discrepency on a AP  below K we need to impose conditions on intervals of length about <img src='http://s0.wp.com/latex.php?latex=K%5E2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='K^2' title='K^2' class='latex' /> or a little less. (If we assume that <img src='http://s0.wp.com/latex.php?latex=x_1%2B...%2Bx_m%3D0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x_1+...+x_m=0' title='x_1+...+x_m=0' class='latex' /> then we can be pretty sure that the partial sums are below <img src='http://s0.wp.com/latex.php?latex=%5Csqrt+m&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt m' title='&#92;sqrt m' class='latex' /> or so.)</p>
<p>Altogether on all HAP we have nlogn/(K^2) conditions; and each one represents an event whose probability is roughly 1/K, so a rough estimate of the overall probability for a sequence to satisfy all these conditions is (1/K)^nlogn/K^2 which should be larger than 2^-n.</p>
<p>So if K is  little more than sqrt log n it looks good.</p>
<p>There are now good news and bad news:</p>
<p>The bad news is that we do not have independence. There are methods to prove the existence of rare events even if there is some slight dependencies (e.g., Lovasz Local Lemma) but you still need much more independence.</p>
<p>The good news is that it seems that the correlation is positive. So if you already assume that sums of <img src='http://s0.wp.com/latex.php?latex=x_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x_i' title='x_i' class='latex' />s is zero (or close to zero) for certain entervals in some HAP then it is more likely that such sums are zero when you take sums along intervals in other HAP. </p>
<p>But the good news are not that good in the sense that I see no (even heuristically) reason to believe that this positive correlation will replace the 1/K with something larger than 1/2 and this will not make a big difference. (But this deserves more thinking.)</p>
<p>What about general AP (just as a sanity test). Here, the n log n is replaced by n^2 so K indeed is expected to be larger. It would be interesting to compare the discrepency results for AP (Roth?) with what the probabilistic heuristic gives to get some intuition.</p>
<p>If such a heuristic can show that the probability for a sequence with low discrepency (say polylog n) is sufficiently large, I see no reason why such low discrepency will force some periodic behavior.</p>
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		<title>By: Sune Kristian Jakobsen</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6277</link>
		<dc:creator><![CDATA[Sune Kristian Jakobsen]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 19:26:56 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6277</guid>
		<description><![CDATA[I &lt;a href=&quot;http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6194&quot; rel=&quot;nofollow&quot;&gt;promised&lt;/a&gt; that I would write something about pseudointegers on the wiki and give a summary. I have written the &lt;a href=&quot;http://michaelnielsen.org/polymath1/index.php?title=Pseudointegers&quot; rel=&quot;nofollow&quot;&gt;page&lt;/a&gt; now, but I haven&#039;t proved as much as I had hoped. Here is what I have found out:

For a pseudointeger $latex x\neq 1= (0,0,\dots)$ we look at the density of pseudointegers that are divisible by x. In one of the models where EDP fails this is 0 for all $latex x\neq 1$ and in another this is 1 for all x. I have proved, that if it is 0 for one x, it is 0 for all $latex x\neq 1$. If it is 1 for a $latex x\neq 1$, it must be 1 for all x. 

It turns out, that for a set X of &quot;pseudointegers&quot; as I defined it &lt;a href=&quot;http://gowers.wordpress.com/2010/02/08/edp7-emergency-post/#comment-6116&quot; rel=&quot;nofollow&quot;&gt;here&lt;/a&gt; (@Tim: sorry for stealing the word) you can find a (non necessarily injective, but non-trivial) function $latex \varphi: X\to \mathbb{R}$ with $latex \varphi(xy)=\varphi(x)\varphi(y)$ and $latex x\leq y \Rightarrow \varphi(x)\leq\varphi(y)$. It is defined such that &lt;i&gt;if&lt;/i&gt; the density of integers divisible by x is $latex d_x\in (0,1)$, then $latex d_x=1/\varphi(x)$. If furthermore the limit

$latex d=\lim_{n\to\infty}\frac{&#124;\varphi(X)\cap (0,n]&#124;}{n} $

exists and $latex d\in (0,1)$ we know that the density $latex d_x$ must exists.

I think it is a good idea to think of pseudointegers as subsets of R, but as Tim noticed &lt;a href=&quot;http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6178&quot; rel=&quot;nofollow&quot;&gt;here&lt;/a&gt; it gives some difficulties (if $latex \alpha&lt;2$ there exists n such that $latex n\alpha&lt;2n-1$), so it might still make sense to use the more general definition.]]></description>
		<content:encoded><![CDATA[<p>I <a href="http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6194" rel="nofollow">promised</a> that I would write something about pseudointegers on the wiki and give a summary. I have written the <a href="http://michaelnielsen.org/polymath1/index.php?title=Pseudointegers" rel="nofollow">page</a> now, but I haven&#8217;t proved as much as I had hoped. Here is what I have found out:</p>
<p>For a pseudointeger <img src='http://s0.wp.com/latex.php?latex=x%5Cneq+1%3D+%280%2C0%2C%5Cdots%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x&#92;neq 1= (0,0,&#92;dots)' title='x&#92;neq 1= (0,0,&#92;dots)' class='latex' /> we look at the density of pseudointegers that are divisible by x. In one of the models where EDP fails this is 0 for all <img src='http://s0.wp.com/latex.php?latex=x%5Cneq+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x&#92;neq 1' title='x&#92;neq 1' class='latex' /> and in another this is 1 for all x. I have proved, that if it is 0 for one x, it is 0 for all <img src='http://s0.wp.com/latex.php?latex=x%5Cneq+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x&#92;neq 1' title='x&#92;neq 1' class='latex' />. If it is 1 for a <img src='http://s0.wp.com/latex.php?latex=x%5Cneq+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x&#92;neq 1' title='x&#92;neq 1' class='latex' />, it must be 1 for all x. </p>
<p>It turns out, that for a set X of &#8220;pseudointegers&#8221; as I defined it <a href="http://gowers.wordpress.com/2010/02/08/edp7-emergency-post/#comment-6116" rel="nofollow">here</a> (@Tim: sorry for stealing the word) you can find a (non necessarily injective, but non-trivial) function <img src='http://s0.wp.com/latex.php?latex=%5Cvarphi%3A+X%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;varphi: X&#92;to &#92;mathbb{R}' title='&#92;varphi: X&#92;to &#92;mathbb{R}' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=%5Cvarphi%28xy%29%3D%5Cvarphi%28x%29%5Cvarphi%28y%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;varphi(xy)=&#92;varphi(x)&#92;varphi(y)' title='&#92;varphi(xy)=&#92;varphi(x)&#92;varphi(y)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=x%5Cleq+y+%5CRightarrow+%5Cvarphi%28x%29%5Cleq%5Cvarphi%28y%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x&#92;leq y &#92;Rightarrow &#92;varphi(x)&#92;leq&#92;varphi(y)' title='x&#92;leq y &#92;Rightarrow &#92;varphi(x)&#92;leq&#92;varphi(y)' class='latex' />. It is defined such that <i>if</i> the density of integers divisible by x is <img src='http://s0.wp.com/latex.php?latex=d_x%5Cin+%280%2C1%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d_x&#92;in (0,1)' title='d_x&#92;in (0,1)' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=d_x%3D1%2F%5Cvarphi%28x%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d_x=1/&#92;varphi(x)' title='d_x=1/&#92;varphi(x)' class='latex' />. If furthermore the limit</p>
<p><img src='http://s0.wp.com/latex.php?latex=d%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%5Cfrac%7B%7C%5Cvarphi%28X%29%5Ccap+%280%2Cn%5D%7C%7D%7Bn%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d=&#92;lim_{n&#92;to&#92;infty}&#92;frac{|&#92;varphi(X)&#92;cap (0,n]|}{n} ' title='d=&#92;lim_{n&#92;to&#92;infty}&#92;frac{|&#92;varphi(X)&#92;cap (0,n]|}{n} ' class='latex' /></p>
<p>exists and <img src='http://s0.wp.com/latex.php?latex=d%5Cin+%280%2C1%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d&#92;in (0,1)' title='d&#92;in (0,1)' class='latex' /> we know that the density <img src='http://s0.wp.com/latex.php?latex=d_x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d_x' title='d_x' class='latex' /> must exists.</p>
<p>I think it is a good idea to think of pseudointegers as subsets of R, but as Tim noticed <a href="http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6178" rel="nofollow">here</a> it gives some difficulties (if <img src='http://s0.wp.com/latex.php?latex=%5Calpha%3C2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;alpha&lt;2' title='&#92;alpha&lt;2' class='latex' /> there exists n such that <img src='http://s0.wp.com/latex.php?latex=n%5Calpha%3C2n-1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n&#92;alpha&lt;2n-1' title='n&#92;alpha&lt;2n-1' class='latex' />), so it might still make sense to use the more general definition.</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6276</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 19:12:27 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6276</guid>
		<description><![CDATA[Hmm ... immediately after submitting that I realized it was very close to what I was trying to do earlier with the continuous kernel. But that doesn&#039;t stop me wanting to think about it.]]></description>
		<content:encoded><![CDATA[<p>Hmm &#8230; immediately after submitting that I realized it was very close to what I was trying to do earlier with the continuous kernel. But that doesn&#8217;t stop me wanting to think about it.</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6275</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 19:11:19 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6275</guid>
		<description><![CDATA[Something else that would help a lot in the process of seeing whether any diagonalizing-of-matrices approach could work is to think about what &lt;em&gt;any&lt;/em&gt; proof that $latex \langle f,Tf\rangle$ is large could possibly look like. For example, it is obvious that if the smallest eigenvalue of $latex T$ is $latex c&gt;0$, then $latex \langle f,Tf\rangle\geq c\&#124;f\&#124;_2^2$, since the best you can do is choose an eigenvector with eigenvalue $latex c$. However, we also know that that is not how a proof of EDP could look, since there are functions $latex f$ such that $latex \&#124;f\&#124;_2$ is large and the discrepancy is small, such as our old friend 1, -1, 0, 1, -1, 0, 1, -1, 0, ...

What I have been suggesting is an intermediate result, in which we assume not just a lower bound on $latex \&#124;f\&#124;_2$ but also an upper bound on $latex \&#124;\hat{f}\&#124;_\infty$. How might that help?

Well, if we knew that the only eigenvectors with very small eigenvalues were very trigonometric in shape, then we might be getting somewhere, since then the only way for $latex \&#124;f\&#124;_2$ to be large without $latex f$ correlating with a trigonometric function would be for $latex f$ to have a reasonable projection on to the space generated by eigenvectors with larger eigenvalues.

It&#039;s quite plausible that low-eigenvalue eigenvectors are trigonometric in nature, since periodic examples seem to give us a rich supply of low-discrepancy sequences (and hence sequences that are mapped to something small by our matrix). So this might be something that&#039;s not too hard to investigate. 

Why isn&#039;t this just restating the problem? I think it&#039;s because I&#039;d hope that we could find such a big supply of functions that are mapped to small things that we would &quot;run out of the small part&quot; of the spectral decomposition. It might not be necessary to find the eigenvectors. Sorry to be a bit vague here. I think the next thing to do is see what the matrix does to trigonometric functions.]]></description>
		<content:encoded><![CDATA[<p>Something else that would help a lot in the process of seeing whether any diagonalizing-of-matrices approach could work is to think about what <em>any</em> proof that <img src='http://s0.wp.com/latex.php?latex=%5Clangle+f%2CTf%5Crangle&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;langle f,Tf&#92;rangle' title='&#92;langle f,Tf&#92;rangle' class='latex' /> is large could possibly look like. For example, it is obvious that if the smallest eigenvalue of <img src='http://s0.wp.com/latex.php?latex=T&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='T' title='T' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=c%3E0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='c&gt;0' title='c&gt;0' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Clangle+f%2CTf%5Crangle%5Cgeq+c%5C%7Cf%5C%7C_2%5E2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;langle f,Tf&#92;rangle&#92;geq c&#92;|f&#92;|_2^2' title='&#92;langle f,Tf&#92;rangle&#92;geq c&#92;|f&#92;|_2^2' class='latex' />, since the best you can do is choose an eigenvector with eigenvalue <img src='http://s0.wp.com/latex.php?latex=c&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='c' title='c' class='latex' />. However, we also know that that is not how a proof of EDP could look, since there are functions <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5C%7Cf%5C%7C_2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;|f&#92;|_2' title='&#92;|f&#92;|_2' class='latex' /> is large and the discrepancy is small, such as our old friend 1, -1, 0, 1, -1, 0, 1, -1, 0, &#8230;</p>
<p>What I have been suggesting is an intermediate result, in which we assume not just a lower bound on <img src='http://s0.wp.com/latex.php?latex=%5C%7Cf%5C%7C_2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;|f&#92;|_2' title='&#92;|f&#92;|_2' class='latex' /> but also an upper bound on <img src='http://s0.wp.com/latex.php?latex=%5C%7C%5Chat%7Bf%7D%5C%7C_%5Cinfty&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;|&#92;hat{f}&#92;|_&#92;infty' title='&#92;|&#92;hat{f}&#92;|_&#92;infty' class='latex' />. How might that help?</p>
<p>Well, if we knew that the only eigenvectors with very small eigenvalues were very trigonometric in shape, then we might be getting somewhere, since then the only way for <img src='http://s0.wp.com/latex.php?latex=%5C%7Cf%5C%7C_2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;|f&#92;|_2' title='&#92;|f&#92;|_2' class='latex' /> to be large without <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> correlating with a trigonometric function would be for <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> to have a reasonable projection on to the space generated by eigenvectors with larger eigenvalues.</p>
<p>It&#8217;s quite plausible that low-eigenvalue eigenvectors are trigonometric in nature, since periodic examples seem to give us a rich supply of low-discrepancy sequences (and hence sequences that are mapped to something small by our matrix). So this might be something that&#8217;s not too hard to investigate. </p>
<p>Why isn&#8217;t this just restating the problem? I think it&#8217;s because I&#8217;d hope that we could find such a big supply of functions that are mapped to small things that we would &#8220;run out of the small part&#8221; of the spectral decomposition. It might not be necessary to find the eigenvectors. Sorry to be a bit vague here. I think the next thing to do is see what the matrix does to trigonometric functions.</p>
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		<title>By: Ian Martin</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6274</link>
		<dc:creator><![CDATA[Ian Martin]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 18:01:40 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6274</guid>
		<description><![CDATA[I&#039;m entering a busy phase but will try to have a look at these at some point.  (Given the addictiveness of this, I&#039;ll probably get round to it fairly soon...)

Regarding the experimental evidence on prime squares vs thrice primes: isn&#039;t this what we see happening based on the approximations &lt;a href=&quot;http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6254&quot; rel=&quot;nofollow&quot;&gt;here&lt;/a&gt; and &lt;a href=&quot;http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6255&quot; rel=&quot;nofollow&quot;&gt;here&lt;/a&gt;?  For example, $latex Af(n) \approx 10\pi/(3 \sqrt{n})$ if $latex n$ is a thrice prime and $latex Af(n) \approx 3\pi/\sqrt{n}$ if $latex n$ is a prime squared.

Admittedly, these approximations are (i) upper bounds and (ii) upper bounds on the behaviour of the first iterate of $latex f(n)$, rather than the eigenvector/fixed-point, but it seems an encouraging sign.

Incidentally, I think it&#039;s also possible to provide lower bounds for this first iterate.  For example if $latex n=p$ a prime, then $latex [(n-1)\pi+4n \arctan \sqrt{n}]/(2n^{3/2}) \leq Af(n) \leq (2n-1)\pi/n^{3/2}$, which looks like $latex 3\pi/(2 \sqrt{n}) \leq Af(n) \leq 2\pi/\sqrt{n}$ if $latex n$ is large.  I haven&#039;t yet done this in the cases $latex n=pq$ or $latex n=p^{2}$, but will try to do this at some stage soon unless you think this is a dead end?

Finally, another experimental observation: it also looks as though the primes cubed are worse than being twice a prime squared.]]></description>
		<content:encoded><![CDATA[<p>I&#8217;m entering a busy phase but will try to have a look at these at some point.  (Given the addictiveness of this, I&#8217;ll probably get round to it fairly soon&#8230;)</p>
<p>Regarding the experimental evidence on prime squares vs thrice primes: isn&#8217;t this what we see happening based on the approximations <a href="http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6254" rel="nofollow">here</a> and <a href="http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6255" rel="nofollow">here</a>?  For example, <img src='http://s0.wp.com/latex.php?latex=Af%28n%29+%5Capprox+10%5Cpi%2F%283+%5Csqrt%7Bn%7D%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Af(n) &#92;approx 10&#92;pi/(3 &#92;sqrt{n})' title='Af(n) &#92;approx 10&#92;pi/(3 &#92;sqrt{n})' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is a thrice prime and <img src='http://s0.wp.com/latex.php?latex=Af%28n%29+%5Capprox+3%5Cpi%2F%5Csqrt%7Bn%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Af(n) &#92;approx 3&#92;pi/&#92;sqrt{n}' title='Af(n) &#92;approx 3&#92;pi/&#92;sqrt{n}' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is a prime squared.</p>
<p>Admittedly, these approximations are (i) upper bounds and (ii) upper bounds on the behaviour of the first iterate of <img src='http://s0.wp.com/latex.php?latex=f%28n%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f(n)' title='f(n)' class='latex' />, rather than the eigenvector/fixed-point, but it seems an encouraging sign.</p>
<p>Incidentally, I think it&#8217;s also possible to provide lower bounds for this first iterate.  For example if <img src='http://s0.wp.com/latex.php?latex=n%3Dp&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n=p' title='n=p' class='latex' /> a prime, then <img src='http://s0.wp.com/latex.php?latex=%5B%28n-1%29%5Cpi%2B4n+%5Carctan+%5Csqrt%7Bn%7D%5D%2F%282n%5E%7B3%2F2%7D%29+%5Cleq+Af%28n%29+%5Cleq+%282n-1%29%5Cpi%2Fn%5E%7B3%2F2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[(n-1)&#92;pi+4n &#92;arctan &#92;sqrt{n}]/(2n^{3/2}) &#92;leq Af(n) &#92;leq (2n-1)&#92;pi/n^{3/2}' title='[(n-1)&#92;pi+4n &#92;arctan &#92;sqrt{n}]/(2n^{3/2}) &#92;leq Af(n) &#92;leq (2n-1)&#92;pi/n^{3/2}' class='latex' />, which looks like <img src='http://s0.wp.com/latex.php?latex=3%5Cpi%2F%282+%5Csqrt%7Bn%7D%29+%5Cleq+Af%28n%29+%5Cleq+2%5Cpi%2F%5Csqrt%7Bn%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='3&#92;pi/(2 &#92;sqrt{n}) &#92;leq Af(n) &#92;leq 2&#92;pi/&#92;sqrt{n}' title='3&#92;pi/(2 &#92;sqrt{n}) &#92;leq Af(n) &#92;leq 2&#92;pi/&#92;sqrt{n}' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is large.  I haven&#8217;t yet done this in the cases <img src='http://s0.wp.com/latex.php?latex=n%3Dpq&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n=pq' title='n=pq' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=n%3Dp%5E%7B2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n=p^{2}' title='n=p^{2}' class='latex' />, but will try to do this at some stage soon unless you think this is a dead end?</p>
<p>Finally, another experimental observation: it also looks as though the primes cubed are worse than being twice a prime squared.</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6273</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 17:20:49 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6273</guid>
		<description><![CDATA[How about making the first half of the $latex x_i$ equal to 1 and the second half equal to -1?]]></description>
		<content:encoded><![CDATA[<p>How about making the first half of the <img src='http://s0.wp.com/latex.php?latex=x_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x_i' title='x_i' class='latex' /> equal to 1 and the second half equal to -1?</p>
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		<title>By: Sune Kristian Jakobsen</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6272</link>
		<dc:creator><![CDATA[Sune Kristian Jakobsen]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 17:19:19 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6272</guid>
		<description><![CDATA[This might be a stupid question, but I&#039;ll ask it anyway: Does there exist a $latex C\in \mathbb{N}$ such that for any $latex n\in\mathbb{N}$ there is a finite {1,-1}-sequence $latex x_1,x_2,\dots,x_n$ such that for any $latex d\in\mathbb{N}$:

$latex &#124;\sum_{i=1}^{\lfloor n/d\rfloor}x_{id}&#124;\leq C$ 

That is, we don&#039;t care for partial sums, but only for HAPs that goes all the way to n.]]></description>
		<content:encoded><![CDATA[<p>This might be a stupid question, but I&#8217;ll ask it anyway: Does there exist a <img src='http://s0.wp.com/latex.php?latex=C%5Cin+%5Cmathbb%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='C&#92;in &#92;mathbb{N}' title='C&#92;in &#92;mathbb{N}' class='latex' /> such that for any <img src='http://s0.wp.com/latex.php?latex=n%5Cin%5Cmathbb%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n&#92;in&#92;mathbb{N}' title='n&#92;in&#92;mathbb{N}' class='latex' /> there is a finite {1,-1}-sequence <img src='http://s0.wp.com/latex.php?latex=x_1%2Cx_2%2C%5Cdots%2Cx_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x_1,x_2,&#92;dots,x_n' title='x_1,x_2,&#92;dots,x_n' class='latex' /> such that for any <img src='http://s0.wp.com/latex.php?latex=d%5Cin%5Cmathbb%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d&#92;in&#92;mathbb{N}' title='d&#92;in&#92;mathbb{N}' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%7C%5Csum_%7Bi%3D1%7D%5E%7B%5Clfloor+n%2Fd%5Crfloor%7Dx_%7Bid%7D%7C%5Cleq+C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|&#92;sum_{i=1}^{&#92;lfloor n/d&#92;rfloor}x_{id}|&#92;leq C' title='|&#92;sum_{i=1}^{&#92;lfloor n/d&#92;rfloor}x_{id}|&#92;leq C' class='latex' /> </p>
<p>That is, we don&#8217;t care for partial sums, but only for HAPs that goes all the way to n.</p>
]]></content:encoded>
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	<item>
		<title>By: Jason Dyer</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6271</link>
		<dc:creator><![CDATA[Jason Dyer]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 16:42:23 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6271</guid>
		<description><![CDATA[While it&#039;s fun to think about the completely general version of the structure (for example, cycles of odd degree cause unbounded discrepancy), for the sake of the original problem it might be useful to set some conditions:

Given a set of nodes $latex a_1, ... a_n$:

1. One labelled set of edges connects $latex a_i$ to $latex a_i+1$ for all &lt;em&gt;i&lt;/em&gt; from 1 to &lt;em&gt;n&lt;/em&gt;-1.

2. For any edge from $latex a_i$ to $latex a_j$, &lt;em&gt;i&lt;/em&gt; is less than &lt;em&gt;j&lt;/em&gt;.

3. Given a set consisting of all labelled edges of a given label, any traversal starting from the root node of the set can traverse the entire set of edges.

4. No set of edges is a subset of another set (this prevents having arbitrary start points).

Given these conditions, the minimal set of nodes where the discrepancy must be greater than 1 is 4.

Proof: Consider every possible set of edges using 3 nodes.

set A: 1-&gt;2-&gt;3
set B: 1-&gt;3

Then $latex a_1 = 1$, $latex a_2 = -1$, $latex a_3 = -1$ has a discrepancy of 1.

However, consider these sets with 4 nodes:

set A: 1-&gt;2-&gt;3-&gt;4
set B: 1-&gt;3
set C: 1-&gt;4

Then no combinations of +1 and -1 (set A constrains the possibilities to + - + -, - + + -, + - - +, and - + - +) avoids having a discrepancy of 2 in some set of edges.]]></description>
		<content:encoded><![CDATA[<p>While it&#8217;s fun to think about the completely general version of the structure (for example, cycles of odd degree cause unbounded discrepancy), for the sake of the original problem it might be useful to set some conditions:</p>
<p>Given a set of nodes <img src='http://s0.wp.com/latex.php?latex=a_1%2C+...+a_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_1, ... a_n' title='a_1, ... a_n' class='latex' />:</p>
<p>1. One labelled set of edges connects <img src='http://s0.wp.com/latex.php?latex=a_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_i' title='a_i' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=a_i%2B1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_i+1' title='a_i+1' class='latex' /> for all <em>i</em> from 1 to <em>n</em>-1.</p>
<p>2. For any edge from <img src='http://s0.wp.com/latex.php?latex=a_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_i' title='a_i' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=a_j&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_j' title='a_j' class='latex' />, <em>i</em> is less than <em>j</em>.</p>
<p>3. Given a set consisting of all labelled edges of a given label, any traversal starting from the root node of the set can traverse the entire set of edges.</p>
<p>4. No set of edges is a subset of another set (this prevents having arbitrary start points).</p>
<p>Given these conditions, the minimal set of nodes where the discrepancy must be greater than 1 is 4.</p>
<p>Proof: Consider every possible set of edges using 3 nodes.</p>
<p>set A: 1-&gt;2-&gt;3<br />
set B: 1-&gt;3</p>
<p>Then <img src='http://s0.wp.com/latex.php?latex=a_1+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_1 = 1' title='a_1 = 1' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=a_2+%3D+-1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_2 = -1' title='a_2 = -1' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=a_3+%3D+-1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_3 = -1' title='a_3 = -1' class='latex' /> has a discrepancy of 1.</p>
<p>However, consider these sets with 4 nodes:</p>
<p>set A: 1-&gt;2-&gt;3-&gt;4<br />
set B: 1-&gt;3<br />
set C: 1-&gt;4</p>
<p>Then no combinations of +1 and -1 (set A constrains the possibilities to + &#8211; + -, &#8211; + + -, + &#8211; - +, and &#8211; + &#8211; +) avoids having a discrepancy of 2 in some set of edges.</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6270</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 15:50:59 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6270</guid>
		<description><![CDATA[Your generalization is in a similar spirit to &lt;a href=&quot;http://gowers.wordpress.com/2010/01/16/the-erds-discrepancy-problem-v/#comment-5244&quot; rel=&quot;nofollow&quot;&gt;a generalization that Terry suggested&lt;/a&gt; a few weeks ago, but it seems to be more general still. It would be very nice if one could come up with a graph-theoretic conjecture that was significantly more combinatorial than EDP but still hard.]]></description>
		<content:encoded><![CDATA[<p>Your generalization is in a similar spirit to <a href="http://gowers.wordpress.com/2010/01/16/the-erds-discrepancy-problem-v/#comment-5244" rel="nofollow">a generalization that Terry suggested</a> a few weeks ago, but it seems to be more general still. It would be very nice if one could come up with a graph-theoretic conjecture that was significantly more combinatorial than EDP but still hard.</p>
]]></content:encoded>
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	<item>
		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6269</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 15:35:29 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6269</guid>
		<description><![CDATA[I want to try once more to explain why I&#039;m interested in the eigenvalues and eigenvectors of the matrix $latex A_{xy}=(x,y)/(x+y)$, partly for my own benefit.

The starting point is a wish to prove EDP by means of a suitable averaging argument. That is, instead of proving that &lt;em&gt;there exists&lt;/em&gt; a HAP $latex P$ such that $latex &#124;\sum_{x\in P}f(x)&#124;\geq C$, one attempts to prove that the sum is large &lt;em&gt;on average&lt;/em&gt;.

There is a great deal of flexibility in how one interprets this, since we can apply a monotonic function to the sum before taking the average, and we can also introduce weights. To be more explicit, suppose that $latex \phi$ is some strictly increasing function. Then $latex x\geq C$ if and only if $latex \phi(x)\geq\phi(C)$. Therefore, if $latex H$ is a set of HAPs, and to each $latex P\in H$ we assign a weight $latex w_P$ in such a way that $latex \sum_{P\in H}w_P=1$, then a sufficient condition for there to exist a HAP with $latex &#124;\sum_{x\in P}f(x)&#124;\geq C$ is that $latex \sum_{P\in H}w_P\phi(&#124;\sum_{x\in P}f(x)&#124;)\geq \phi(C)$.

The most obvious choice of function $latex \phi$ is $latex \phi(x)=x^2$, since this is gives us a positive-definite quadratic form in $latex f$ and potentially makes available to us the tools of linear algebra.

We can think of this quadratic form as follows. Let $latex \Lambda$ be the linear map from $latex \mathbb{R}^n$ to $latex \mathbb{R}^H$ that&#039;s defined by $latex \Lambda f(P)=\sum_{x\in P}f(x)$, and let $latex \Delta$ be the diagonal map from $latex \mathbb{R}^H$ to itself that has matrix $latex \Delta_{PP}=w_P$. Then the quadratic form takes the column vector $latex f$ to $latex f^T\Lambda^T\Delta\Lambda f$. It ought to be useful if we could diagonalize this quadratic form, which is equivalent to finding $latex n$ functions $latex g_1,\dots,g_n$ such that $latex \sum_Pw_P\langle f,P\rangle^2=\sum_{i=1}^n\langle f,g_i\rangle^2$. The most obvious way to try to do that is to take the symmetric $latex n\times n$ matrix $latex \Lambda^T\Delta\Lambda$ and find an orthonormal basis of eigenvectors. But it occurs to me while writing this that there might be other useful ways of diagonalizing the quadratic form. Or maybe one would be happy to settle for more than $latex n$ functions $latex g_i$, as long as they were somehow &quot;nice&quot;. It is of course always open to us to choose the weights to try to make them nice.]]></description>
		<content:encoded><![CDATA[<p>I want to try once more to explain why I&#8217;m interested in the eigenvalues and eigenvectors of the matrix <img src='http://s0.wp.com/latex.php?latex=A_%7Bxy%7D%3D%28x%2Cy%29%2F%28x%2By%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A_{xy}=(x,y)/(x+y)' title='A_{xy}=(x,y)/(x+y)' class='latex' />, partly for my own benefit.</p>
<p>The starting point is a wish to prove EDP by means of a suitable averaging argument. That is, instead of proving that <em>there exists</em> a HAP <img src='http://s0.wp.com/latex.php?latex=P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='P' title='P' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%7C%5Csum_%7Bx%5Cin+P%7Df%28x%29%7C%5Cgeq+C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|&#92;sum_{x&#92;in P}f(x)|&#92;geq C' title='|&#92;sum_{x&#92;in P}f(x)|&#92;geq C' class='latex' />, one attempts to prove that the sum is large <em>on average</em>.</p>
<p>There is a great deal of flexibility in how one interprets this, since we can apply a monotonic function to the sum before taking the average, and we can also introduce weights. To be more explicit, suppose that <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is some strictly increasing function. Then <img src='http://s0.wp.com/latex.php?latex=x%5Cgeq+C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x&#92;geq C' title='x&#92;geq C' class='latex' /> if and only if <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28x%29%5Cgeq%5Cphi%28C%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;phi(x)&#92;geq&#92;phi(C)' title='&#92;phi(x)&#92;geq&#92;phi(C)' class='latex' />. Therefore, if <img src='http://s0.wp.com/latex.php?latex=H&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='H' title='H' class='latex' /> is a set of HAPs, and to each <img src='http://s0.wp.com/latex.php?latex=P%5Cin+H&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='P&#92;in H' title='P&#92;in H' class='latex' /> we assign a weight <img src='http://s0.wp.com/latex.php?latex=w_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='w_P' title='w_P' class='latex' /> in such a way that <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7BP%5Cin+H%7Dw_P%3D1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{P&#92;in H}w_P=1' title='&#92;sum_{P&#92;in H}w_P=1' class='latex' />, then a sufficient condition for there to exist a HAP with <img src='http://s0.wp.com/latex.php?latex=%7C%5Csum_%7Bx%5Cin+P%7Df%28x%29%7C%5Cgeq+C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|&#92;sum_{x&#92;in P}f(x)|&#92;geq C' title='|&#92;sum_{x&#92;in P}f(x)|&#92;geq C' class='latex' /> is that <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7BP%5Cin+H%7Dw_P%5Cphi%28%7C%5Csum_%7Bx%5Cin+P%7Df%28x%29%7C%29%5Cgeq+%5Cphi%28C%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{P&#92;in H}w_P&#92;phi(|&#92;sum_{x&#92;in P}f(x)|)&#92;geq &#92;phi(C)' title='&#92;sum_{P&#92;in H}w_P&#92;phi(|&#92;sum_{x&#92;in P}f(x)|)&#92;geq &#92;phi(C)' class='latex' />.</p>
<p>The most obvious choice of function <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28x%29%3Dx%5E2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;phi(x)=x^2' title='&#92;phi(x)=x^2' class='latex' />, since this is gives us a positive-definite quadratic form in <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> and potentially makes available to us the tools of linear algebra.</p>
<p>We can think of this quadratic form as follows. Let <img src='http://s0.wp.com/latex.php?latex=%5CLambda&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Lambda' title='&#92;Lambda' class='latex' /> be the linear map from <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D%5En&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mathbb{R}^n' title='&#92;mathbb{R}^n' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D%5EH&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mathbb{R}^H' title='&#92;mathbb{R}^H' class='latex' /> that&#8217;s defined by <img src='http://s0.wp.com/latex.php?latex=%5CLambda+f%28P%29%3D%5Csum_%7Bx%5Cin+P%7Df%28x%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Lambda f(P)=&#92;sum_{x&#92;in P}f(x)' title='&#92;Lambda f(P)=&#92;sum_{x&#92;in P}f(x)' class='latex' />, and let <img src='http://s0.wp.com/latex.php?latex=%5CDelta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta' title='&#92;Delta' class='latex' /> be the diagonal map from <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D%5EH&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mathbb{R}^H' title='&#92;mathbb{R}^H' class='latex' /> to itself that has matrix <img src='http://s0.wp.com/latex.php?latex=%5CDelta_%7BPP%7D%3Dw_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta_{PP}=w_P' title='&#92;Delta_{PP}=w_P' class='latex' />. Then the quadratic form takes the column vector <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=f%5ET%5CLambda%5ET%5CDelta%5CLambda+f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f^T&#92;Lambda^T&#92;Delta&#92;Lambda f' title='f^T&#92;Lambda^T&#92;Delta&#92;Lambda f' class='latex' />. It ought to be useful if we could diagonalize this quadratic form, which is equivalent to finding <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> functions <img src='http://s0.wp.com/latex.php?latex=g_1%2C%5Cdots%2Cg_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='g_1,&#92;dots,g_n' title='g_1,&#92;dots,g_n' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5Csum_Pw_P%5Clangle+f%2CP%5Crangle%5E2%3D%5Csum_%7Bi%3D1%7D%5En%5Clangle+f%2Cg_i%5Crangle%5E2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_Pw_P&#92;langle f,P&#92;rangle^2=&#92;sum_{i=1}^n&#92;langle f,g_i&#92;rangle^2' title='&#92;sum_Pw_P&#92;langle f,P&#92;rangle^2=&#92;sum_{i=1}^n&#92;langle f,g_i&#92;rangle^2' class='latex' />. The most obvious way to try to do that is to take the symmetric <img src='http://s0.wp.com/latex.php?latex=n%5Ctimes+n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n&#92;times n' title='n&#92;times n' class='latex' /> matrix <img src='http://s0.wp.com/latex.php?latex=%5CLambda%5ET%5CDelta%5CLambda&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Lambda^T&#92;Delta&#92;Lambda' title='&#92;Lambda^T&#92;Delta&#92;Lambda' class='latex' /> and find an orthonormal basis of eigenvectors. But it occurs to me while writing this that there might be other useful ways of diagonalizing the quadratic form. Or maybe one would be happy to settle for more than <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> functions <img src='http://s0.wp.com/latex.php?latex=g_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='g_i' title='g_i' class='latex' />, as long as they were somehow &#8220;nice&#8221;. It is of course always open to us to choose the weights to try to make them nice.</p>
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		<title>By: Jason Dyer</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6268</link>
		<dc:creator><![CDATA[Jason Dyer]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 14:56:10 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6268</guid>
		<description><![CDATA[Sorry, I should add it&#039;s only equivalent to our problem if we only allow traversals to start at the root node of a particular set of labelled edges.]]></description>
		<content:encoded><![CDATA[<p>Sorry, I should add it&#8217;s only equivalent to our problem if we only allow traversals to start at the root node of a particular set of labelled edges.</p>
]]></content:encoded>
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		<title>By: Jason Dyer</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6267</link>
		<dc:creator><![CDATA[Jason Dyer]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 14:53:42 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6267</guid>
		<description><![CDATA[I&#039;ve been thinking about a graph-theoretical generalization of the problem, which unfortunately doesn&#039;t include the multiplicative feature.

Define an infinite set of nodes $latex a_1, a_2, ...$ such that given a node $latex a_i$ there is a directed edge labelled $latex i$ from $latex a_{i(n)}$ to $latex a_{i(n+1)}$ for all $latex n\in \mathbb{N}$.

Give each node a value 1 or -1. Consider a traversal starting at a node moving along edges with the same label a finite number of times; then the discrepancy of a given traversal is the absolute value of the sum of all nodes visited. Asking if it is possible for the discrepancy to be bounded is equivalent to our problem.

What&#039;s interesting is the graph doesn&#039;t have to follow the number system. Have a set of nodes (finite or infinite) $latex a_1, a_2, ...$ such that there are labelled directed edges, but allow the edges to be arbitrary. Then there are interesting questions like; given a discrepancy &lt;em&gt;d&lt;/em&gt;, what is a minimal graph (in terms of nodes and/or edges) where the discrepancy is greater than &lt;em&gt;d&lt;/em&gt;? What conditions cause the discrepancy to &quot;break&quot;? My hope is we can isolate certain graph theoretic properties which cause the logic to break and translate those into number theoretic properties we can search for (perhaps very rare ones, but ones we can prove exist nonetheless).]]></description>
		<content:encoded><![CDATA[<p>I&#8217;ve been thinking about a graph-theoretical generalization of the problem, which unfortunately doesn&#8217;t include the multiplicative feature.</p>
<p>Define an infinite set of nodes <img src='http://s0.wp.com/latex.php?latex=a_1%2C+a_2%2C+...&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_1, a_2, ...' title='a_1, a_2, ...' class='latex' /> such that given a node <img src='http://s0.wp.com/latex.php?latex=a_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_i' title='a_i' class='latex' /> there is a directed edge labelled <img src='http://s0.wp.com/latex.php?latex=i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='i' title='i' class='latex' /> from <img src='http://s0.wp.com/latex.php?latex=a_%7Bi%28n%29%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_{i(n)}' title='a_{i(n)}' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=a_%7Bi%28n%2B1%29%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_{i(n+1)}' title='a_{i(n+1)}' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=n%5Cin+%5Cmathbb%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n&#92;in &#92;mathbb{N}' title='n&#92;in &#92;mathbb{N}' class='latex' />.</p>
<p>Give each node a value 1 or -1. Consider a traversal starting at a node moving along edges with the same label a finite number of times; then the discrepancy of a given traversal is the absolute value of the sum of all nodes visited. Asking if it is possible for the discrepancy to be bounded is equivalent to our problem.</p>
<p>What&#8217;s interesting is the graph doesn&#8217;t have to follow the number system. Have a set of nodes (finite or infinite) <img src='http://s0.wp.com/latex.php?latex=a_1%2C+a_2%2C+...&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_1, a_2, ...' title='a_1, a_2, ...' class='latex' /> such that there are labelled directed edges, but allow the edges to be arbitrary. Then there are interesting questions like; given a discrepancy <em>d</em>, what is a minimal graph (in terms of nodes and/or edges) where the discrepancy is greater than <em>d</em>? What conditions cause the discrepancy to &#8220;break&#8221;? My hope is we can isolate certain graph theoretic properties which cause the logic to break and translate those into number theoretic properties we can search for (perhaps very rare ones, but ones we can prove exist nonetheless).</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6266</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 14:31:08 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6266</guid>
		<description><![CDATA[Answer: it seems not. 

A few experimental questions that interest me are as follows.

(i) What does the restriction of the graph of $latex f$ to numbers of the form $latex 4p$ look like? 

(ii) More generally, if you pick a large prime $latex p$ and look at the ratios $latex f(mp)/f(p)$ for small values of $latex m$, then what does that look like as a function of $latex m$?

(iii) Does that function have more or less the same shape as $latex \xi$ itself?

(iv) What does $latex \xi$ look like at integers of the form $latex pq$ with $latex p$ and $latex q$ primes of roughly the same size?]]></description>
		<content:encoded><![CDATA[<p>Answer: it seems not. </p>
<p>A few experimental questions that interest me are as follows.</p>
<p>(i) What does the restriction of the graph of <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f' title='f' class='latex' /> to numbers of the form <img src='http://s0.wp.com/latex.php?latex=4p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='4p' title='4p' class='latex' /> look like? </p>
<p>(ii) More generally, if you pick a large prime <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> and look at the ratios <img src='http://s0.wp.com/latex.php?latex=f%28mp%29%2Ff%28p%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f(mp)/f(p)' title='f(mp)/f(p)' class='latex' /> for small values of <img src='http://s0.wp.com/latex.php?latex=m&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='m' title='m' class='latex' />, then what does that look like as a function of <img src='http://s0.wp.com/latex.php?latex=m&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='m' title='m' class='latex' />?</p>
<p>(iii) Does that function have more or less the same shape as <img src='http://s0.wp.com/latex.php?latex=%5Cxi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi' title='&#92;xi' class='latex' /> itself?</p>
<p>(iv) What does <img src='http://s0.wp.com/latex.php?latex=%5Cxi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi' title='&#92;xi' class='latex' /> look like at integers of the form <img src='http://s0.wp.com/latex.php?latex=pq&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='pq' title='pq' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q' title='q' class='latex' /> primes of roughly the same size?</p>
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		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6264</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 11:30:38 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6264</guid>
		<description><![CDATA[I&#039;m still trying to make a decent guess in response to &lt;a href=&quot;http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6258&quot; rel=&quot;nofollow&quot;&gt;Ian&#039;s question&lt;/a&gt;. I&#039;ve tried several things and not got very far yet. But maybe some useful clues could come from the ratios that are there in the data. For instance, it looks as though $latex \xi(2p)/\xi(p)$ tends to a limit as $latex p$ tends to infinity (along the primes). So this gives us some number $latex \rho(2)$ to think about. 

I&#039;m still puzzled about why squares of primes should behave as they do. It seems that being a square of a prime is worse than being three times a prime, and much worse than being a $latex pq$ for primes $latex p$ and $latex q$ of comparable size. 

One thing I&#039;m about to look at, without much hope of a miracle: is the eigenvector a multiplicative (as opposed to completely multiplicative) function?]]></description>
		<content:encoded><![CDATA[<p>I&#8217;m still trying to make a decent guess in response to <a href="http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6258" rel="nofollow">Ian&#8217;s question</a>. I&#8217;ve tried several things and not got very far yet. But maybe some useful clues could come from the ratios that are there in the data. For instance, it looks as though <img src='http://s0.wp.com/latex.php?latex=%5Cxi%282p%29%2F%5Cxi%28p%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi(2p)/&#92;xi(p)' title='&#92;xi(2p)/&#92;xi(p)' class='latex' /> tends to a limit as <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> tends to infinity (along the primes). So this gives us some number <img src='http://s0.wp.com/latex.php?latex=%5Crho%282%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;rho(2)' title='&#92;rho(2)' class='latex' /> to think about. </p>
<p>I&#8217;m still puzzled about why squares of primes should behave as they do. It seems that being a square of a prime is worse than being three times a prime, and much worse than being a <img src='http://s0.wp.com/latex.php?latex=pq&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='pq' title='pq' class='latex' /> for primes <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q' title='q' class='latex' /> of comparable size. </p>
<p>One thing I&#8217;m about to look at, without much hope of a miracle: is the eigenvector a multiplicative (as opposed to completely multiplicative) function?</p>
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		<title>By: H Matthew</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6263</link>
		<dc:creator><![CDATA[H Matthew]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 11:02:06 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6263</guid>
		<description><![CDATA[I suppose one could also ask in terms of the rotations and reflections.]]></description>
		<content:encoded><![CDATA[<p>I suppose one could also ask in terms of the rotations and reflections.</p>
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		<title>By: H Matthew</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6262</link>
		<dc:creator><![CDATA[H Matthew]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 10:47:04 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6262</guid>
		<description><![CDATA[One could also view the problem as reducing to a sequence of movements on a unit hypercube.  It would be interesting to see whether the movements take on any patterns, or rather if the movements are restricted to edge, face or volume movements.]]></description>
		<content:encoded><![CDATA[<p>One could also view the problem as reducing to a sequence of movements on a unit hypercube.  It would be interesting to see whether the movements take on any patterns, or rather if the movements are restricted to edge, face or volume movements.</p>
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		<title>By: Ian Martin</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6261</link>
		<dc:creator><![CDATA[Ian Martin]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 10:06:00 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6261</guid>
		<description><![CDATA[&lt;a href=&quot;http://www.stanford.edu/~iwrm/mobiusinversion.png&quot; rel=&quot;nofollow&quot;&gt;Here&#039;s&lt;/a&gt; a plot of the Mobius inversion of the experimental $latex \xi$ using the 2000x2000 matrix $latex A_{xy}$.

There are some visible patterns: for example, the clearly defined upper stripe is the primes, and the most obvious stripe below is the twice-primes.]]></description>
		<content:encoded><![CDATA[<p><a href="http://www.stanford.edu/~iwrm/mobiusinversion.png" rel="nofollow">Here&#8217;s</a> a plot of the Mobius inversion of the experimental <img src='http://s0.wp.com/latex.php?latex=%5Cxi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi' title='&#92;xi' class='latex' /> using the 2000&#215;2000 matrix <img src='http://s0.wp.com/latex.php?latex=A_%7Bxy%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A_{xy}' title='A_{xy}' class='latex' />.</p>
<p>There are some visible patterns: for example, the clearly defined upper stripe is the primes, and the most obvious stripe below is the twice-primes.</p>
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	<item>
		<title>By: gowers</title>
		<link>http://gowers.wordpress.com/2010/02/19/edp8-what-next/#comment-6260</link>
		<dc:creator><![CDATA[gowers]]></dc:creator>
		<pubDate>Tue, 23 Feb 2010 09:28:49 +0000</pubDate>
		<guid isPermaLink="false">http://gowers.wordpress.com/?p=1533#comment-6260</guid>
		<description><![CDATA[Nothing did, but an idea occurred to me, which was that perhaps $latex \xi$ is of the form $latex \xi(n)=\sum_{d&#124;n}\rho(d)$ for some function $latex \rho$. If so, then we&#039;d be able to find $latex \rho$ by M&#246;bius inverting $latex \xi$: that is, $latex \rho(n)=\sum_{d&#124;n}\mu(d)\xi(n/d)$. It&#039;s a stab in the dark, but do we get anything interesting if we M&#246;bius invert the function $latex \xi$ that we&#039;re given experimentally?]]></description>
		<content:encoded><![CDATA[<p>Nothing did, but an idea occurred to me, which was that perhaps <img src='http://s0.wp.com/latex.php?latex=%5Cxi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi' title='&#92;xi' class='latex' /> is of the form <img src='http://s0.wp.com/latex.php?latex=%5Cxi%28n%29%3D%5Csum_%7Bd%7Cn%7D%5Crho%28d%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi(n)=&#92;sum_{d|n}&#92;rho(d)' title='&#92;xi(n)=&#92;sum_{d|n}&#92;rho(d)' class='latex' /> for some function <img src='http://s0.wp.com/latex.php?latex=%5Crho&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;rho' title='&#92;rho' class='latex' />. If so, then we&#8217;d be able to find <img src='http://s0.wp.com/latex.php?latex=%5Crho&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;rho' title='&#92;rho' class='latex' /> by M&ouml;bius inverting <img src='http://s0.wp.com/latex.php?latex=%5Cxi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi' title='&#92;xi' class='latex' />: that is, <img src='http://s0.wp.com/latex.php?latex=%5Crho%28n%29%3D%5Csum_%7Bd%7Cn%7D%5Cmu%28d%29%5Cxi%28n%2Fd%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;rho(n)=&#92;sum_{d|n}&#92;mu(d)&#92;xi(n/d)' title='&#92;rho(n)=&#92;sum_{d|n}&#92;mu(d)&#92;xi(n/d)' class='latex' />. It&#8217;s a stab in the dark, but do we get anything interesting if we M&ouml;bius invert the function <img src='http://s0.wp.com/latex.php?latex=%5Cxi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi' title='&#92;xi' class='latex' /> that we&#8217;re given experimentally?</p>
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